What is the molar concentration of As( III ) in a solution if 24.80 mL of 0.120 M KBrO_3 is needed to titrate 48.65 mL of the As( III ) solution? The balanced equation is
3H_3AsO_3(aq)} + BrO_3^-(aq) ----> Br^-(aq) + 3H_3AsO_4(aq)
_ is used to show subscript
^ used to show superscript
Molarity formula is....
Molarity=Moles/Liters
I took the molarity formula applied it t the .0248L and .120molar and then set that equal to molarity x liters(.04865).
The answer i got was .0611716 molar, but that is wrong i guess any help?
3H_3AsO_3(aq)} + BrO_3^-(aq) ----> Br^-(aq) + 3H_3AsO_4(aq)
_ is used to show subscript
^ used to show superscript
Molarity formula is....
Molarity=Moles/Liters
I took the molarity formula applied it t the .0248L and .120molar and then set that equal to molarity x liters(.04865).
The answer i got was .0611716 molar, but that is wrong i guess any help?
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